average sq deviation from the mean

subtracting the individual scores - x from the mean - m for x - m

then square the deviation scores, (x - m) x (x - m) {we do this to ensure you do not have a zero]

that will give u x - m^2

round to two decimal points when rounding 5's, round it with a 50/50 up or down;; "flip a coin"

• subtract the mean from every score
• Square every deviation
• Sum all the squared
• Divide the sum of

squares by total number in the sample (N) 𝑆𝐷2 = σ(𝑋 − 𝑀)2 𝑁SD2 =48.80/5 = 9.76 Standard Deviation  Typical amount that the individual scores vary or deviate from the sample mean  The average distance of a score from the mean  It is the square root of the variance 𝑆𝐷 = Σ(𝑋 − 𝑀)2 𝑁 SD2 =48.80/5 = 9.76